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Starting PONTORMATICA home

E 'have created a new blog: PONTORMATICA , find the link with the others, which aims to extend beyond the contributions of students, but to all persons (doecenti or not) are fields concerned to propose questions, discussions of interesting or educational.

would be important were the contributions of the authors of the teaching issue, then, in this original sense.

The Blog, after a period of experimentation, opens with a contribution from the curator (SP) that affornta a theme of nature mathematical physics.

hope is to the liking, visit us!

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Physics: Physics of the vacuum cleaner running

Abstract: The post is reserved for the time being, the contributions of the class III C.

It is this: Consider now the vacuum cleaner in uniform motion in the forward direction. The suction nozzle has a length l along the forward direction (see figure).

Determine the maximum speed V and the vacuum cleaner may have if you want to draw masses of value M / 2 where M is the value of the mass drawn in a position to vacuum cleaner off (previous post).

still apply the characteristics of the previous post in relation to the suction force of the nozzle and the height from the ground.

going to try to check the "third eye ", as the physicist!

Bonuses : (+ +) for comments to be significant; Deals : (++++++) for the complete solution.

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Consider a vacuum cleaner whose suction nozzle (see diagram) has the size in the forward direction. For height h

the ground, it can be assumed that the suction power remains constant and known value F and that a particle can be considered " sucked " if it reaches the quota h speed v 0 note.

Under these conditions, notes that the sizes: l, h, F, v 0 gravitational acceleration g , determine: The maximum M mass drawn through the vacuum cleaner quiet.

The little problem is not easy (deliberately) but can be solved using the laws of dynamics.

I look forward to attempts to solve, even partially, to the authors of which will be assigned a (+), then if someone finds the correct solution and then complete: (++++).

Enjoy!